The voltage divider, divides the voltage but also reduces the current to zero.By making a voltage divider, i am getting an exact divided voltage(12 volt) with no current. It suppose to divide the voltage and not the current.
For example, if i want to divide 12 volt from 24 volt. I had used two equal resistor
(i.e)R1=10K and R2=10K
input volt vin= 24
Vout=Vin*R2 / (R1+R2)
How to divide the voltage without decreasing the current???
Advance thanks..
By dividing by half the value of each resistor, you keep the original current. Is there anything not mentioned in this question, or are you not very familiar with the Ohm's law ?
The voltage divider, divides the voltage but also reduces the current to zero.By making a voltage divider, i am getting an exact divided voltage(12 volt) with no current. It suppose to divide the voltage and not the current.
For example, if i want to divide 12 volt from 24 volt. I had used two equal resistor
(i.e)R1=10K and R2=10K
input volt vin= 24
Thank you eduardo, i understand now when to use voltage divider and buck converter. Can you show some examples or calculations of buck converter. I have searched but its not clear or understandable.
Thank you eduardo, i understand now when to use voltage divider and buck converter. Can you show some examples or calculations of buck converter. I have searched but its not clear or understandable.
Input Voltage = 24Vcc
Output Voltage = 12Vcc
Output Current = ??? (The most important, who decides the type of converter)
Type of Load = ??? (for maximun ripple and voltage regulation)
According to this it will be preferable:
- Resistor divider or resistor series.
- 7812
- 7812+transistor boost
- Step down converter
Input volt = 24
Output volt = 12
Input current = output current
Load = motor
According to this spec, it seems buck converter will suits. I thought of trying to make buck converter circuit rather than buying, so that i may get a little idea about voltage and current dividers.
Voltage divider used for divide voltage with zero current.
Buck converter (step down) used to reduce voltage, but output current will be as same input.
Can you guide me to make curcuit for buck converter.
The first statment is true for linear regulators. But is is not true for (switching) buck converters (And if it really is the case with a buck converter, then the buck converter makes no sense)
Can you guide me to make curcuit for buck converter.
There are many buck converter ICs. (I´d never build one on my own. It takes too much time and i don´t think it is cheaper)
Many converter Ic manufactureres have interactive selection guides to choose the best fit.
The datasheet describes all to build a complete buck converter circuit. With all calculations, layout considerations and so on. Additinal information can be found in "application notes".
If you know a manufacturer of those ICs --> visit the internet pages
If you don´t know a manufacturer, then go to a electronic parts distributor´s internet pages. Then you will see some devices and the name of the manufacturers.
But as already said: You urgently need to know the expectable load current. Add some margin.
My input supply= 24v
Where my load (motor) needs only 12v. So i need to divide the supply voltage and i have to give load.
And i am also interested to know and willing to make buck ( step down) circuit.