jstefanop
Member level 2
So I have a single PLL pin that needs .9v and draws no more than 5ma of current. I don't want to waste a whole LDO just for such a small task, so i want to use the 1.8v output from an existing LDO and drop it down to .9v for this pin. What 2-3 low cost component count solution do I have for this problem?
My first thoughts was I would just use a zener diode, but after some search a .9v breakdown voltage zener does not seem to exist. A simple resistor voltage divider also won't work since I don't know the exact current draw of the pin(could be 1ma..could be 4.4ma).
What I'm thinking now is to just use a regular diode, that has a .9v forward voltage at the low current I need. Any thoughts?
My first thoughts was I would just use a zener diode, but after some search a .9v breakdown voltage zener does not seem to exist. A simple resistor voltage divider also won't work since I don't know the exact current draw of the pin(could be 1ma..could be 4.4ma).
What I'm thinking now is to just use a regular diode, that has a .9v forward voltage at the low current I need. Any thoughts?