I am using a Zener Diode to establish a 2.5V reference voltage.
I forget the part number of Zener but it is connected with a 30K resistor.
When I put the sensor on my circuit this Zener diode lost regulation.
The following are the data.
Input voltage is 5V.
Desired Reference is 2.5V
Current reference voltage is 0.8V
Serial connection resistor with Zener diode is 30K suggested by datasheet.
Can I use the following way to find the current load resistance?
Finding current: (5 – 0.8 )/30000 = 0.14mA
Finding desired current: (5-2.5)/30000 = 0.083mA
The minimum load resistance before Zener diode loses regulation is: (5-2.5)/0.083mA = 30K
The current load resistance: 0.8/(0.14-0.083) = 14K
Are you sure you have connected the Zener diode in the right direction .. ???
As a diode it has ~0.8V voltage drop in one direction and in the reversed configuration (Zener effect) it should show the Zener voltage, which, in your case, is 2.5V ..
On the other hand, 30k looks pretty big for this job ..
Try to force 1mA current through it, that is 2.2k-to-2.7k resistor, and see how it goes ..
If sensor does not draw more current I would not recommend more than 10kΩ series resistor, but even if you have zener that is only 100mW, current could be set up to 40mA. If we take, let's say that your zener diode voltage was specified @10mA, resistor would be 250Ω. If you don't have power saving requirements that is probably what your series resistor should be. To round it up to some value that you can find very easy, 270Ω.
As Borber said at 140µA it really doesn't matter much if current is going to be much higher, you should run at least 3mA through Zener diode. If you run 10mA you should be safe for any change in load. Don't forget to use capacitors in parallel with zener. Elko 10µF with 0.1µF ceramic would be great addition.
If you need reference to be more stable, using integrated reference will yield much better performance. TL431 for example is widelly available and is used in same manner as zener diode, but more stable.
There are many precision voltage reference IC's. Sometime it is satisfactory to use simple resistor voltage divider (potentiometer) from 5V supply voltage.
As Siniša mentioned TL431 can be used as it is widely available component and such reference can be adjustable.
There are plenty of 2.5V shunt references, that consume below 50 uA, e. g. standard LM385-2.5 with 20 uA, it's really not a problem to find a usable device. However, as you already found out, the sensor input current has to be considered. If there's no specification (sounds strange), you can lower the resistance until the reference operates at it's specified voltage and add some extra.
Just to point out, for reason of low consumption requirement and unknown input current, best choise would be series regulator - reference. Consumption of reference would be small consumption of reference and input current of input and nothing extra like some spare current you need with shunt reference. And you also insure that input has enough current even if it changes because some internal conditions of your sensor.
EDA_hg81,
In order for the zener to provide its specified output, the current thru the zener must be equal to, or close to the specified test current (It). See the zener data sheet for It.
Let
It = the zener test current
Il = the load current
Vu = the unregulated voltage
Vz = the regulated voltage
Under load, the current Ir thru the series resistor R will equal the Zener test current plus the load current. Then
Rs = (Vu-Vz)/(It + Il)
As the current thru the zener decreases, its equivalent resistance increases and the regulation gets worse.
Regards,
Kral
Zener diodes less than about 5.6V are lousy voltage regulators. Their voltage drops when their current drops, like a simple resistor. Their voltage also drops when the temperature drops.
Zener diodes from 5.6V to about 6.8V are pretty good voltage regulators. Their voltage remains constant when their current or temperature change.