query in matrix subtraction

[krishnavenis]

View attachment document.do.dochi
here i am sending an attachment. In this i need to solve matrix. how to subtract column matrix from square matrix. Is there any rules for such subtraction. i need suggestions. plz check this.Looking forward for ur reply.

 

[hartejpal]

I think such an operation is not defined.
Please refer to
https://www.purplemath.com/modules/mtrxadd.htm

 

[krishnavenis]

hi sir,
if such a subtraction is not possible, then how can i solve this paper. can u give me some suggestions

 

[hartejpal]

hi sir,
if such a subtraction is not possible, then how can i solve this paper. can u give me some suggestions

Sorry buddy.
Can't figure out a way.

Try to write to the author of this paper, with this query.

 

[jeeudr]

I assume that you are referring to the equation \[ E = (K-\frac{1}{2}ID)^{-1}S \]

In the current form, it looks quite erroneous.

By \[ ID \], I think that they mean that elements of column vector \[ D \] are split into their own separate column (like a diagonal matrix, with diagonal elements taken from \[ D \] ).

Otherwise, \[ K - \frac{1}{2}I D \] makes no sense, because \[ K \] is a matrix and \[ D \] is a vector.

 

[hartejpal]

By \[ ID \], I think that they mean that elements of column vector \[ D \] are split into their own separate column (like a diagonal matrix, with diagonal elements taken from \[ D \] ).

Could be. But, then it is an improper use of notation.
A nxn identity matrix multiplied to a nx1 vector would result in a nx1 vector only.

Otherwise, \[ K - \frac{1}{2}I D \] makes no sense, because \[ K \] is a matrix and \[ D \] is a vector.

True.
I believe only the author of this paper can best clarify, why he has used such notation.

 

[krishnavenis]

thank you so much for ur response sir. I will try in this way.