Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Proper Selection of a Current Transformer, Multirange Ammeter Design

Status
Not open for further replies.

imranahmed

Advanced Member level 3
Advanced Member level 3
Joined
Dec 4, 2011
Messages
822
Helped
3
Reputation
6
Reaction score
3
Trophy points
1,298
Location
Karachi,Pakistan
Visit site
Activity points
6,533
Do you know about Current Transformer?

I need to measure current C.T from my meter. The issue is that the C.T`s are available for different current ratings.
for example:
1) 30/5 means if 30amps current pass through C.T it will induced 5 amps current in its secondary and
if 15amps current pass through C.T it will induced 2.5 amps current and so on.But according to formula
Is=(Np x Ip)/Ns==> Is=(1 x 15)/6=2.5A for 30Amps C.T.

2) 60/5 means if 60amps current pass through C.T it will induced 5 amps current in its secondary and
if 15amps current pass through C.T it will induced 2.5 amps current and so on.But according to formula
Is=(Np x Ip)/Ns==> Is=(1 x 15)/12=1.25A for 60Amps C.T.

3) How to calibrate my voltmeter for both C.T`s?
 

Hi Imran,

here again.

Your software has to know what current transformer you use.
This can be made with a switch (30A/60A) or by keypress... or any other manual input.

* digital with IIC:
If you have a connector for both CTs and you have some pins free on this connector then you can mount a simple IIC EEPROM into the plug of the CT.
In the EEPROM you can stoer the information whether 30A or 60A. You can also store a complete calibration value: like (29.87A full scale). Then you are most flexible and it is easy to use.

* digital with port pin:
just use one or two port input pins and use a pullup in the one CT connector and a pulldown in the other CT connector.

* analog ADC solution:
If you don´t like the EEPROM stuff, then a simple resistor can work also. Lets say a 6kOhms resistor for 60A and a 3kOhms resistor for 30A. Read it it with the ADC and decide what CT is connected.

* analog solution without calibration:
Another possibility is to apply the shunt to the CT. So maybe a 120mOhms to the 60/5 A CT to get 10mV per Ampere
and a 60 mOhms shunt to the 30/5 A CT and get 10mV per Ampere also --> no calibration needed.

One question: why not allways use the 60/5 A CT? the benifit of the 30/5 A CT is not that much.

(Or why not use simply a shunt for 60A and a chopper stabilized OPAMP to amplify the signal. For Ptot < 0.5W @ 60A --> 120uOhms. And 7.2mV....OK forget about this. With a good layout and well chosen amplifiers it is possible, but i think in your application it makes more problems than benifit....)

So i hope there is at least one good solution for you...

Hope this helps
Klaus
 
Dear KlausST,

Actually I need to build ammeter for multi-range CT`s.

for example:

If my ammeter able to read all range 0/5 to 1000/5 amps so it good but all CT`s have
its own ratio.If I calibrate my ammeter for 30/5A CT it will not work with 60/5 or others.
What can I do for build multi-range CT operated ammeter?
 

Hi Imran,

Can you calibrate for 5A and show 0 ... 100%?
Then it's true for all x/5A CTs.

Klaus
 
Can you calibrate for 5A and show 0 ... 100%?

Dear KlausST,

This is I need you told but how? :thinker:

- - - Updated - - -

Dear KlausST,

Please visit another new thread "Digital Multimeter Design".
 

Hi,

DC: (active compensation CTs) take an average of a number of conversions and multiply it so, that if you apply 5A on the input the display shows "100.0"

AC: true RMS, or what? If so, then calculste the value and calibrate it the same way as with DC.

Or is the problem elsewhere?

Klaus
 
Dear KlausST,

I do not need to display in percentage I need to display actual value.

For True RMS AC.


If I use 40m-ohms burden resistor for 5A CT.

V=I x R
V=5A x 40m-ohms
V=200mV.

V=I x R
V=2.5A x 40m-ohms
V=100mV.


But it is true if I use only 30/5 or x/5 one CT meter but all CT`s compensation is the problem.
 

Hi,

Another possibility:
Use a rotary switch that switches different shunt values according to your CT values.

Or use a rotary switch (maybe with binary coding) and connect to port pins to tell the ucontroller which CT you use.


Klaus
 

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top