Problem of variable format reading in MPLAB

[ecaits]

Hello Sirs,

I am working on PIC16F877 using hi-tech c compiler.

if i declare one integer variable say i = 200. then when i observe it in watch window of mplab then it shows equivalent hex value i.e. C8.

If I want to do division operation with i, say a = i/6.82; then it always take hex value in i but i want to do division operation with decimal only.

How i can solve this problem???

 

[anjalimidhuna]

0xC8 is the equivalent hex of 200(decimal). your ans will be in hex convert it into decimal in order to get the result you expect

 

[ecaits]

But when i convert the hex to decimal and take that decimal value in variable then that variable also shows the hex value, not decimal value.... that is the problem...

 

[firoz3321]

In watch window u can choose to see HEX or Decimal or BINARY or all.
That should solve the problem.

 

[GOODPROGRAMMER]

u should take typecast and u will get only decimal value


exp .......a=(int)(i/6.82)

 

[FvM]

exp .......a=(int)(i/6.82)

The result type depends on the data type of a, not a type cast. Automatic type conversion according to C standard takes place. (You probably should read a C text book to deserve your name )

Either a is an integer type, then the result will be displayed as such and you can read it in the watch window in the decimal display, if you enabled the decimal column or chose decimal as the default format. Or it's float type, then you need to select the proper float format used by your compiler.