Dear Sir,
Dear Sir, Thankyou for the reply.
Please forgive me on my ignorance. As I am completely new and working on my own I am facing problem with basic issues which experienced persons might assume to be just common sense.
I thought that dividing the reference value to a low mV input for error amplifier will lead to low mV output of the error amplifier which is then the input for the compensator amplifier which has the positive terminal grounded. And from books I read that the op amp to work in linear range with amplification the difference between the two inputs has to be very small.
Also I thought having a capacitance of 100pF will give me the integral term.
Thankyou.