rubixx
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OK, well the forum says elementary questions, so should be easy ..
My question is:
If i increase the voltage in my circuit by adding extra batteries in series, and then drop to nominal voltage
with a resistor, will 100% of excess voltage be dissipated by the resistor in form of heat and leave me with the same mAH as when i started?
Given connecting batteries in parallel would be easier in most cases, but in a flashlight tube, for example, when there is 0 tolerance between the cylinder walls and batteries and adding a resistor would be easier.. I cant figure this out!!
My question is:
If i increase the voltage in my circuit by adding extra batteries in series, and then drop to nominal voltage
with a resistor, will 100% of excess voltage be dissipated by the resistor in form of heat and leave me with the same mAH as when i started?
Given connecting batteries in parallel would be easier in most cases, but in a flashlight tube, for example, when there is 0 tolerance between the cylinder walls and batteries and adding a resistor would be easier.. I cant figure this out!!