Power Conversion Efficiency?

[poachedpig]

I have a problem with getting the power efficiency of my passive rectifier.



I tried to use the formula found in this already closed thread: https://www.edaboard.com/threads/260495/

I used this formula

=tperiod
∫((vplus(t)-|vminus(t)|)*(iplus(t)-|iminus(t)|)*dt) / tperiod
t=0

I am confused if it is applicable to my testbench. And the result seems very far from the expected output. I have difficulty measuring the Pinput or even the Vinput and Iinput since it is in AC.

Is it possible to use Vrms and Irms to represent as my Pinput?

or

What if, I'm going to convert my peak input voltage to dBm. Can I use the equivalent power, like in this table: http://ifmaxp1.ifm.uni-hamburg.de/DBM.shtml

If so, then my input power will remain constant. I'm in doubt but is this correct?

 

[AdamsN]

1)does you converter implement pfc in the input?

2)The input ac voltages have the same phase?

If the above are both true then the power at the input is Pin = 2*Vrms*Irms

But as you said your rectifier is a passive one. So in your occasion i would say that the converter efficiency is

n= Pdc_output / S_input= Vdc*Idc/(2*Vrms*Irms)

 

[poachedpig]

1. No, the input does not implement pfc

2. The AC input has a difference of 180


I will try to use this formula

n= Pdc_output / S_input= Vdc*Idc/(2*Vrms*Irms)

and see what happens...