PIN Diode - relationship between dc current and power handling

[amp1]

hello,
I'm looking for the relationship between dc current and power handling of pin diode
If i want to pass through pin diode with 20W (@100Mhz), how can i calculate the Idc that i need to supply

for example MA4P504-1072T
https://www.firstsourceinc.com/DataSheets/MACom Tech/MA4P504-1072T.pdf
in the Features wrote "High Power Handling" . How can i know how "high" it is, and which Idc i need to supply to get this "High Power Handling"

( I'm using this Pin Diode for RF Switch )

Thanks

 

[dick_freebird]

Your "on" current needs to exceed your through-current
crest at max power and min load, to remain at maximum
C value; you probably need to margin it up some, to keep
second order effects like C-V modulation from adding
distortion.

Likewise your "off" voltage needs to exceed the voltage
crest in the other direction, without the benefit of the
loadng onthe other side.

 

[chuckey]

The data sheet is confusing, it says Vca max = 1V under limiting parameters, it the says Vca @ 50mA = 1V, it then gives graphs with I = 100 mA. Also with a P = 3w at 1V, would indicate a much bigger current, but none is given. I think 20 W into 50Ω is about 33V at .6A . The device has a high reverse voltage rating - 500V. So if you operate it with a circuit impedance of 200 Ω, then for 20W, V = 66V, I = 330 mA, still too much, try a higher circuit impedance, the trouble is that the shunt capacity will disrupt the circuit more as the impedance is raised.
Frank