[SOLVED] PCB Designing in ARES (Proteus) Help Needed?

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I am designing a PCB for PIC18F8722 Micro-Controller which is having a very small package i think TQFP80.
I just want to bring all pins out as with DIP Packages.
So i Want to design a Square shape PCB having 20 pin Connectors on each side.

But the problem is that, i don't want to put vias inside controller, so can anyone tell me how to protect that i proteus.
And yes i am going to use ARES Auto-Router for this Purpose.

Due to some reason i am not able to place snapshot.

I just want there must be no vias inside the micro-controller.

Please help very urgent

 

[alexan_e]

I have routed a similar breakout board but I did it manually.

I'm not sure the autorouter can do a good job but you can try, read https://www.edaboard.com/threads/239737/#post1025827

 

[xpress_embedo]

I have routed a similar breakout board but I did it manually.

I'm not sure the autorouter can do a good job but you can try, read https://www.edaboard.com/threads/239737/#post1025827

Thanks i used manual routing and completed my pcb.

 

[alexan_e]

It is usually the best solution.
As a hint , when you are making a PCB that is symmetric like a break out board then for a square chip you can make the tracks of one side and just copy then to the other three sides (using rotation and/or mirroring) and if it is a two side chip you can also copy one side to the other

 

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Thanks Alex but i didn't get that properly.
Actually i had to put the crystal and some capacitors on that board, means minimum circuit to run the controller.
Thats why i can't use the mirror technique here.

 

[alexan_e]

I meant a board with just the chip , no other components, for example