ringo888
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Hi,
I'm having trouble with switching off a P-Channel MOSFET which supplies power to an ADC (please see attached schematic). The idea was a "belt and braces" measure to ensure we could cycle the power of the ADC as this particular part has know to hang-up.
Although the p-mosfet is switching power to the ADC when the gate Vg is tied low (i.e. Vgs=-5V) by the digital isolator (NetLabel ADC_EN3), when the output of the isolator is high i.e. 5V the p-mosfet does not turn off and you can see ~3.8V on the output.
Any ideas as to why as I would have expected it to as Vgs=0V?
I have isolated the output of the isolator and you can tie this to 5V or 0V and the output of the p-mosfet switches, would this suggest there isn't sufficient drive coming from the digital isolator?
Any suggestions would be welcome, thanks
Regards,
Ringo
I'm having trouble with switching off a P-Channel MOSFET which supplies power to an ADC (please see attached schematic). The idea was a "belt and braces" measure to ensure we could cycle the power of the ADC as this particular part has know to hang-up.
Although the p-mosfet is switching power to the ADC when the gate Vg is tied low (i.e. Vgs=-5V) by the digital isolator (NetLabel ADC_EN3), when the output of the isolator is high i.e. 5V the p-mosfet does not turn off and you can see ~3.8V on the output.
Any ideas as to why as I would have expected it to as Vgs=0V?
I have isolated the output of the isolator and you can tie this to 5V or 0V and the output of the p-mosfet switches, would this suggest there isn't sufficient drive coming from the digital isolator?
Any suggestions would be welcome, thanks
Regards,
Ringo