dreamyboy_999
Member level 2
What does physically happen when a receiver antenna in Open circuit/ and short circuit mode is exposed to RF signal? Is the power reflected back?
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Wonder what a dissipative short circuit is? An ideal short has zero ohms and thus can't dissipate power.
A non-ideal antenna might have internal losses which can show with any load, also open circuit. We would need to analyze the antenna design details.
An unloaded antenna without internal losses doesn't absorb any power from an electromagnetic field, but diffracts it to some extent.
Yes, there can't be a current at an open wire antenna end. But contradiction to what? It's not said that the open circuit dipole halves must act as lambda/4 resonators. There can be still some current induced in the wire center.but I faced a contradiction...I assume the current needs to be zero at the both ends of each petal...But how can that be possible without keeping the wavelength unchanged?
How does current flow in the antenna? Do the photons induce true AC, or is it AC with a DC component
Wonder what a dissipative short circuit is? An ideal short has zero ohms and thus can't dissipate power.
Antenna's don't work like this. The antenna is always driven by a finite source impedance (transformed free space impedance https://en.wikipedia.org/wiki/Impedance_of_free_space), respectively current and voltage are always finite.An interesting observation: but...
In terms of the current: power P = (current ^2) * resistance. So if the resistance is zero the power will be zero.
In terms of the voltage: power P = (voltage ^2) / resistance. So if the resistance is zero the power will be infinite.