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only for opamp Experts...

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ashad

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Any one calculates the output equation of the following circuit:cry:

Rth =3K at room temperature

75_1173777132.gif
 

if this opamp is an ideal opamp (so V1=V2 and the currents are 0 in the input of the opamp), then
\[V_{1}=V_{2}=V_{ref}\frac{R_{th}}{R_{1}+R_{th}}\]
with a simple voltage dividing.
Then for example use to the V2 node the basic KCL, then the output node is:
\[Vo=Vref \frac{R_{th}(R_{f}R_{l}+R_{f}R_{h}+R_{l}R_{h})}{(R_{1}+R_{th})R_{h}R_{l}}\]
 

Put node equations on the 2nd and 3rd terminal of the op-amp.u'll get

V0 /Rf + Vref/Rh = Vref.Rth/(R1+Rth)[1/Rh+1/R1+1/Rf]
this is the output equation(V0).
 

apply superposition theorem and get the equation for the output. Treat it as two supply voltages V1 & V2
 

ashad said:
Any one calculates the output equation of the following circuit:cry:

Rth =3K at room temperature

75_1173777132.gif

calculate voltage at V1 due to vref and at V2 due to vout. Equat them and solve for Vout...............
 
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i have a question , what program u used to draw the schematic
 

i calculated the result ....... please verify it

Vo = V1(1/Rf+1/Rh/+1/RI) - (Vref/Rh)
 

ashad said:
i calculated the result ....... please verify it

Vo = V1(1/Rf+1/Rh/+1/RI) - (Vref/Rh)

my result is Vo=V1*(Rf/Rh+Rf/Ri+1)-Vref*Rf/Rh
 

gingerjiang said:
ashad said:
i calculated the result ....... please verify it

Vo = V1(1/Rf+1/Rh/+1/RI) - (Vref/Rh)

my result is Vo=V1*(Rf/Rh+Rf/Ri+1)-Vref*Rf/Rh


Really u r expert thanks i will give u five points
 

dear gingerjiang, check your dimension. You'll see that your equation can not be correct.
 

hi demodb

i assume V1=V2

based on KCL on V2 point:
(Vref-V2)/Rh=V2/Ri+(V2-Vo)/Rf
then substitute V2 by V1 and get the result

i'm wrong? please show me
 

I have got this equation.
 

I have got this equation. Pls ignore the previous one.
 

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