[SOLVED] Need to Identify IC

[gherkins]

Hello everyone!
I need help to recognize this IC

Probably somebody had to deal with...

thanks in advance.

 

[AJBotha]

Any idea what its purpose is? Maybe a picture of the entire PCB would help with a description of what product it is?
Is it near a power source? Near a microcontroller? Maybe a transceiver for comms? What I am trying to say is put the IC in context.

 

[D.A.(Tony)Stewart]

**broken link removed**

 

[gherkins]

**broken link removed**

thank you, of course, but there dimensions of body only. :lol: nothing regarding functionality.

but here, it had written something interesting. **broken link removed**`

it is chinese "variant" of LP2951 (voltage regulator).

 

[d123]

Hi, glad you found it, I had a search as well. Nice to know what it is. What does the circuit do, please?

 

[D.A.(Tony)Stewart]

Very low dropout LDO

It could be this.

51A version uses 1.235 Vref

 

[gherkins]

looking at IC's map (shown above) I see electrolytic capacitor which signed as a "1,23 V reference".
-probably somebody knows how it works? Do they really have electrolytic capacitor inside?
-Then one thought comes in my mind...
-probably, they should have quite restricted frist of application . So I suspicion they begin to die of their capaсitors after 7-10 years of running.

Any doubt please. :lol:

 

[bigdogguru]

looking at IC's map (shown above) I see electrolytic capacitor which signed as a "1,23 V reference".

The symbol to which you refer is actually a battery cell symbol, not an electrolytic capacitor symbol, which signifies the 1.23 V voltage reference.

As the diagram indicates, "Representative Block Diagram," which generalizes the internal function of the device, rather than actual specifics of it's design.


BigDog

 

[betwixt]

expanding on that.... just as it doesn't have an electrolytic capcitor inside, it doesn't have a battery either. It is diagramatic of a reference voltage, a stable voltage derived from the input at pin 8.

The "Error Amplifier" compares it with the voltage at pin 7 to control the output voltage. The manufacturer provides a built-in divider available at pin 6 for the convenience of use when 5V is needed but by breaking the connection to pin 7 you can use your own external resistors to set other voltages. If you calculate the voltage at pin 6 from the resistor values you will note it is also ~1.23V.

Brian.

 

[gherkins]

that all was "unscrambled" by competent people...

thanks a lot them!