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[Moved] Speed from motor in rpm

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Vimala04

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can you plz explain the flow of this code?



Code Verilog - [expand]
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module(clk,mpulse,speed);
input clk,mpulse;
output[15:0]speed;
wire [15:0]speed;
reg[31:0]cval, tcount, quot,rem;
reg zero,sts;
wire rfd;
assign speed = (zero?16'd0:quot[15:0]);
always@(posedge clk)
begin
if(!mpulse && sts)
begin
tcount = cval;
sts = 1'b0;
cval = 32'd0;
zero = 1'b0;
end
 
else begin
if(mpulse)
sts = 1'b1;
if(cval = 32'd4000000)
zero = 1'b1;
else
cval = cval+32'd1;
end
end
spddiv speeddiv(.dividend(32'd120000000), .divisor(tcount), .quot(quot, .rem(rem), .clk(clk), .rfd(rfd));
endmodule

 
Last edited by a moderator:

It looks like you are trying to determine the speed by using the relation speed=distance/time. That is the reason you are using a divider block. Looks like the distance is fixed (1200000). But haven't gone into the details. You will need to simulate it and find out
 

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