jktheone
Junior Member level 1
- Joined
- Dec 19, 2010
- Messages
- 16
- Helped
- 1
- Reputation
- 2
- Reaction score
- 1
- Trophy points
- 1,283
- Activity points
- 1,411
Hi fellows,
When reading this book, I have a problem in Example 4.1 in Chapter 4. It introduces a filter's Q caculation when the adjacent channel interfer should have a 35 dB supression. I am confused by the words' for a attentuation of 35 dB (=56.2) at 900.4MHz, this quantity must be equal to R(square)/56.2(square)...' How does the 'R(square)/56.2(square) ' comes out?
When reading this book, I have a problem in Example 4.1 in Chapter 4. It introduces a filter's Q caculation when the adjacent channel interfer should have a 35 dB supression. I am confused by the words' for a attentuation of 35 dB (=56.2) at 900.4MHz, this quantity must be equal to R(square)/56.2(square)...' How does the 'R(square)/56.2(square) ' comes out?
