Jul 29, 2019 #1 P promach Advanced Member level 4 Joined Feb 22, 2016 Messages 1,199 Helped 2 Reputation 4 Reaction score 5 Trophy points 1,318 Activity points 11,636 Expression 4.50 can be obtained by equating the ABCD parameters of the two circuits ? Could anyone advise ? Note: Screenshots below are taken from Microstrip Filters for RF Microwave Applications, 2nd Edition
Expression 4.50 can be obtained by equating the ABCD parameters of the two circuits ? Could anyone advise ? Note: Screenshots below are taken from Microstrip Filters for RF Microwave Applications, 2nd Edition
Jul 29, 2019 #2 pancho_hideboo Advanced Member level 5 Joined Oct 21, 2006 Messages 2,847 Helped 767 Reputation 1,536 Reaction score 733 Trophy points 1,393 Location Real Homeless Activity points 17,490 promach said: Expression 4.50 can be obtained by equating the ABCD parameters of the two circuits ? Click to expand... Yes. Compare [ABCD] of the followings. (1) Transmission Line (2) PI circuit (3) T circuit
promach said: Expression 4.50 can be obtained by equating the ABCD parameters of the two circuits ? Click to expand... Yes. Compare [ABCD] of the followings. (1) Transmission Line (2) PI circuit (3) T circuit
Jul 30, 2019 #3 P promach Advanced Member level 4 Joined Feb 22, 2016 Messages 1,199 Helped 2 Reputation 4 Reaction score 5 Trophy points 1,318 Activity points 11,636 I am still trying to derive the ABCD matrix for the following circuit configuration. Any help ?
Jul 31, 2019 #4 P promach Advanced Member level 4 Joined Feb 22, 2016 Messages 1,199 Helped 2 Reputation 4 Reaction score 5 Trophy points 1,318 Activity points 11,636 The derivation process could be found at page 25 of the pdf attachment Now the question is how to derive expression 4.50 given the above ABCD matrix ? View attachment Microwave_Network_Parameter.pdf
The derivation process could be found at page 25 of the pdf attachment Now the question is how to derive expression 4.50 given the above ABCD matrix ? View attachment Microwave_Network_Parameter.pdf
Aug 4, 2019 #5 pancho_hideboo Advanced Member level 5 Joined Oct 21, 2006 Messages 2,847 Helped 767 Reputation 1,536 Reaction score 733 Trophy points 1,393 Location Real Homeless Activity points 17,490 There is no help since it is too easy. Can you understand following even a liittle ? https://www.edaboard.com/showthread.php?383959-Proof-of-Bode-Fano-criterion&highlight=Bode+fano This is very easy than the above, if you can understand the above even a little.
There is no help since it is too easy. Can you understand following even a liittle ? https://www.edaboard.com/showthread.php?383959-Proof-of-Bode-Fano-criterion&highlight=Bode+fano This is very easy than the above, if you can understand the above even a little.
Aug 14, 2019 #6 P promach Advanced Member level 4 Joined Feb 22, 2016 Messages 1,199 Helped 2 Reputation 4 Reaction score 5 Trophy points 1,318 Activity points 11,636 The following is the derivation process for expression 4.50 ABCD matrix for transmission line at Figure 4.7(a) ABCD matrix for π-circuit network at Figure 4.7(b) Comparing the two ABCD matrices above gives : Applying trigonometry double angle formula :
The following is the derivation process for expression 4.50 ABCD matrix for transmission line at Figure 4.7(a) ABCD matrix for π-circuit network at Figure 4.7(b) Comparing the two ABCD matrices above gives : Applying trigonometry double angle formula :
Aug 17, 2019 #7 P promach Advanced Member level 4 Joined Feb 22, 2016 Messages 1,199 Helped 2 Reputation 4 Reaction score 5 Trophy points 1,318 Activity points 11,636 There is a typo mistake for ABCD matrix for π-circuit network at Figure 4.7(b) Please see the correction below: Ok, now to more detailed part: How to derive expressions (5.3) ? I suppose that this involves eliminating the assumption : ZC << Z0 << ZL Note: In the post above, I have derived expression (5.2) for inductor, which is equivalent to expression (4.50)
There is a typo mistake for ABCD matrix for π-circuit network at Figure 4.7(b) Please see the correction below: Ok, now to more detailed part: How to derive expressions (5.3) ? I suppose that this involves eliminating the assumption : ZC << Z0 << ZL Note: In the post above, I have derived expression (5.2) for inductor, which is equivalent to expression (4.50)