GetDeviceInfo said:In your case, it probably won't matter, but the max current of the shorted secondary is it's VA current divided by it's % impedance.
For example, a 2Kva transformer rated at a 240v secondary and a 2.5% impedance, have a secondary short circuit current of (2000/240)/.025 = 333.33 amps.
If input voltage is sinusoidal, this isn't a good way to measure. Low resistance values is difficult to measure exact. Also LCR meters is not commonly avaiable and most transformators have big H values that is often out of range of the LCR meter.FvM said:The resistive part can be determined with an ohmmeter (4 terminal measurement is required with low ohmic windings), but for the resistive part, an AC measurement or an LCR meter is needed.
If input voltage is sinusoidal, this isn't a good way to measure.
Of course, you are applying an sinusoidal input voltage...Then you must measure current, voltage and angle of the current.
Prototyp_V1.0 said:A better way is to short the secondary output. Then slowly increase voltage from zero volts until input current reach maximum rated (or what you get from VA/V).
Then you must measure current, voltage and angle of the current so you're able to calculate impedance (resistance and reactance separately).
FvM said:If you don't have instruments to measure the current angle directly, it's a simple way to supply the current through a power resistor and calculate the transformer impedance from three voltage measurements.
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