Mar 28, 2013 #1 E-design Advanced Member level 5 Joined Jun 1, 2002 Messages 2,014 Helped 507 Reputation 1,016 Reaction score 408 Trophy points 1,363 Activity points 14,193 I was working on a project and saw the following in the calculations: Laplace[∫ E(t) dt] = E/s^2 Is this correct? Shouldn't it be E/s?
I was working on a project and saw the following in the calculations: Laplace[∫ E(t) dt] = E/s^2 Is this correct? Shouldn't it be E/s?
Mar 28, 2013 #2 Z zorro Advanced Member level 4 Joined Sep 6, 2001 Messages 1,130 Helped 357 Reputation 712 Reaction score 298 Trophy points 1,363 Location Argentina Activity points 8,913 E-design said: I was working on a project and saw the following in the calculations: Laplace[∫ E(t) dt] = E/s^2 Is this correct? Shouldn't it be E/s? Click to expand... It should be Laplace[∫ e(u) du] = E(s)/s provided that the limits of the integral are 0 and t. (I put u as the integration variable in order to avoid confusions.) regards Z
E-design said: I was working on a project and saw the following in the calculations: Laplace[∫ E(t) dt] = E/s^2 Is this correct? Shouldn't it be E/s? Click to expand... It should be Laplace[∫ e(u) du] = E(s)/s provided that the limits of the integral are 0 and t. (I put u as the integration variable in order to avoid confusions.) regards Z