Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Is my explanation of PLL working right, please check this (using 565 IC)....

Status
Not open for further replies.

DEV123

Member level 2
Joined
Feb 28, 2009
Messages
44
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,286
Activity points
1,583
Hello Edaboard,
Please check if my explanation for PLL is right, if any mistakes please correct it.

PLL is a device which makes use of negative feedback so as to match the frequency and phase of a input signal avoiding noise and jitter in it to the ouput signal. So the output signal will have the same frequency and phase of input with no noise component and jitter etc. PLL contains a closed loop of Phase detector (mixer or multiplier) , loop filter (an LPf) and VCO and optionally frequency divider and amplifier etc.

using 565 pll to learn
---------------------
When the input frequency (starts from low frequency) is increased monotonically the pll outputs a free running frequency waveform which is independent of input. When the input frequency reaches a certain point (near to free running frequency f0) the PLL starts its control action (Point A). and the output gets locked till a frequency point in input is reached (point B). similarly in the reverse direction too 2 more points (C and D) as shown below.


fi (input frequency) -------------------------A----------------------------------------------B-----------------------------> forward input freq

<----D--------------------------------------------C---------------------------------------------------- reverse input freq



===================D------------------A-----------f0------------C--------------------B======================== frequency axis

difference AC is the capture and DB is the lock range f0 is the free running frequency.

out of DB the VCO gives out f0 itself.


-----------------

Is this explanation correct. Any thing to add here. Also while doing practicals for me f0 comes out of capture range, what to do?
while measuring f0 should I ground the input?

-Devanand T
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top