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[SOLVED] input referred noise and bandwidth

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Winny_Puuh

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Hi guys, I have a question (again) but it's a short one this time:
if I have a bandwidth of 50kHz, a gain of 50dB --> GBW = 50dB(=316)*50k = 15.8MHz
I want to calculate the input referred noise (thermal) V = 8kT/3*(2/gm1), then I square it, integrate it and here is my question: do i have to multiply it with 15.8Mhz or 50kHz? This makes quite a difference and I dont know which one is the right one...
 

crutschow

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If the 50kHz bandwidth is determined by a filter in the amplifier then you would use a 50kHz bandwidth to calculate the total noise.
 

Winny_Puuh

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Thank you =) that's good news :wink:
 

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