Coust
Member level 2
- Joined
- Oct 1, 2013
- Messages
- 48
- Helped
- 1
- Reputation
- 2
- Reaction score
- 1
- Trophy points
- 8
- Activity points
- 472
Hello there!
I have got this error many times trying to simulate an oscillator and I would be glad if someone could explain me what it means:
I get the "timesteap is too small" error and then, this list appears:
TRAN Tran1[1] <nxp_lib:circuit complet 2NPN proves 1.8V:schematic> time=(0 s->400 ns)
iter = 1 RHS I= 1.916e+08 V= 8.736e+08 k fail RHS I[Vs]= 2.187e+08 (4.9e+02x) dV= 1.406e+06 dI= 1.070e+01
iter = 2 RHS I= 1.497e+04 V= 4.510e+01 k fail RHS V[Var1.L1.i]= 3.207e+01 (1e+03x) dV= 1.724e+00 dI= 3.240e-04
iter = 3 RHS I= 1.434e+04 V= 4.898e+01 k fail RHS V[Var1.L1.i]= 3.207e+01 (1e+03x) dV= 1.148e+00 dI= 2.212e-04
iter = 4 RHS I= 1.410e+04 V= 4.393e+01 k fail RHS V[BJT1.L3.i]= 3.518e+01 (1e+03x) dV= 5.746e-01 dI= 1.668e-04
iter = 5 RHS I= 1.409e+04 V= 4.898e+01 k fail RHS V[BJT1.L3.i]= 2.882e+01 (1e+03x) dV= 5.855e-02 dI= 1.693e-04
iter = 6 RHS I= 1.400e+04 V= 4.393e+01 k fail RHS V[BJT1.L3.i]= 3.518e+01 (1e+03x) dV= 5.772e-01 dI= 8.929e-05
iter = 7 RHS I= 1.385e+04 V= 4.898e+01 k fail RHS V[BJT1.L3.i]= 2.882e+01 (1e+03x) dV= 5.746e-01 dI= 5.642e-05
iter = 8 RHS I= 1.430e+04 V= 4.393e+01 k fail RHS V[BJT1.L3.i]= 3.518e+01 (1e+03x) dV= 5.741e-01 dI= 1.987e-04
iter = 9 RHS I= 1.397e+04 V= 4.898e+01 k fail RHS V[BJT1.L3.i]= 2.882e+01 (1e+03x) dV= 8.614e-01 dI= 1.092e-04
iter =10 RHS I= 1.425e+04 V= 4.393e+01 k fail RHS V[BJT1.L3.i]= 3.518e+01 (1e+03x) dV= 2.873e-01 dI= 2.015e-04
iter = 1 RHS I= 1.916e+08 V= 8.736e+08 k fail RHS I[Vs]= 2.187e+08 (4.9e+02x) dV= 1.406e+06 dI= 6.686e-01
iter = 2 RHS I= 8.429e+04 V= 5.647e+02 k fail RHS V[Var1.L1.i]= 1.439e+03 (1e+03x) dV= 4.604e+00 dI= 3.090e-04
iter = 3 RHS I= 6.249e+04 V= 4.834e+02 k fail RHS V[Var1.L1.i]= 6.093e+02 (1e+03x) dV= 1.378e+01 dI= 2.232e-04
iter = 4 RHS I= 4.111e+04 V= 4.072e+02 k fail RHS V[Var1.L1.i]= 6.093e+02 (1e+03x) dV= 1.383e+01 dI= 1.468e-04
iter = 5 RHS I= 1.040e+05 V= 4.834e+02 k fail RHS V[Var2.L1.i]= 2.335e+03 (1e+03x) dV= 3.143e-01 dI= 3.700e-04
iter = 6 RHS I= 6.706e+04 V= 4.072e+02 k fail RHS V[Var2.L1.i]= 1.761e+03 (1e+03x) dV= 1.378e+01 dI= 2.233e-04
iter = 7 RHS I= 4.111e+04 V= 4.834e+02 k fail RHS V[Var2.L1.i]= 2.335e+03 (1e+03x) dV= 1.380e+01 dI= 1.468e-04
iter = 8 RHS I= 1.040e+05 V= 4.072e+02 k fail RHS V[Var2.L1.i]= 1.761e+03 (1e+03x) dV= 3.143e-01 dI= 3.700e-04
iter = 9 RHS I= 6.706e+04 V= 4.834e+02 k fail RHS V[Var2.L1.i]= 2.335e+03 (1e+03x) dV= 1.378e+01 dI= 2.233e-04
iter =10 RHS I= 4.111e+04 V= 4.072e+02 k fail RHS V[Var2.L1.i]= 1.761e+03 (1e+03x) dV= 1.380e+01 dI= 1.468e-04
iter = 1 RHS I= 1.916e+08 V= 8.736e+08 k fail RHS I[Vs]= 2.187e+08 (4.9e+02x) dV= 1.409e+06 dI= 4.179e-02
iter = 2 RHS I= 1.026e+06 V= 9.981e+03 k fail RHS I[X4.HPFET1.d]= 4.972e+06 (2.1x) dV= 1.617e+03 dI= 2.276e-04
iter = 3 RHS I= 7.239e+05 V= 1.684e+04 k fail RHS I[X4.HPFET1.d]= 3.253e+06 (1.4x) dV= 2.940e+02 dI= 1.669e-04
iter = 4 RHS I= 5.059e+05 V= 8.591e+03 k fail RHS I[X4.HPFET1.d]= 2.416e+06 (1x) dV= 1.471e+02 dI= 1.133e-04
iter = 5 RHS I= 3.011e+05 V= 1.684e+04 k fail RHS I[X4.HPFET1.g]= 4.561e+05 (4.6x) dV= 2.206e+02 dI= 5.625e-05
iter = 6 RHS I= 1.810e+05 V= 8.591e+03 k fail RHS I[X4.HPFET1.g]= 9.427e+05 (9.6x) dV= 7.309e+01 dI= 4.336e-07
iter = 7 RHS I= 1.607e+04 V= 1.684e+04 k fail RHS V[BJT1.L6.i]= 8.571e+04 (1e+03x) dV= 7.505e+01 dI= 8.549e-07
iter = 8 RHS I= 2.905e+05 V= 8.591e+03 k fail RHS I[X4.HPFET1.g]= 1.392e+06 (14x) dV= 7.726e+01 dI= 5.700e-05
iter = 9 RHS I= 2.285e+05 V= 1.684e+04 k fail RHS I[X4.HPFET1.g]= 4.819e+05 (4.9x) dV= 2.944e+02 dI= 5.462e-05
iter =10 RHS I= 1.744e+05 V= 8.591e+03 k fail RHS I[X4.HPFET1.g]= 9.284e+05 (9.4x) dV= 7.452e+01 dI= 2.815e-06
It seems some convergence problem with this devices, isn't it? Any tips to fix it?
Ty very much!
I have got this error many times trying to simulate an oscillator and I would be glad if someone could explain me what it means:
I get the "timesteap is too small" error and then, this list appears:
TRAN Tran1[1] <nxp_lib:circuit complet 2NPN proves 1.8V:schematic> time=(0 s->400 ns)
iter = 1 RHS I= 1.916e+08 V= 8.736e+08 k fail RHS I[Vs]= 2.187e+08 (4.9e+02x) dV= 1.406e+06 dI= 1.070e+01
iter = 2 RHS I= 1.497e+04 V= 4.510e+01 k fail RHS V[Var1.L1.i]= 3.207e+01 (1e+03x) dV= 1.724e+00 dI= 3.240e-04
iter = 3 RHS I= 1.434e+04 V= 4.898e+01 k fail RHS V[Var1.L1.i]= 3.207e+01 (1e+03x) dV= 1.148e+00 dI= 2.212e-04
iter = 4 RHS I= 1.410e+04 V= 4.393e+01 k fail RHS V[BJT1.L3.i]= 3.518e+01 (1e+03x) dV= 5.746e-01 dI= 1.668e-04
iter = 5 RHS I= 1.409e+04 V= 4.898e+01 k fail RHS V[BJT1.L3.i]= 2.882e+01 (1e+03x) dV= 5.855e-02 dI= 1.693e-04
iter = 6 RHS I= 1.400e+04 V= 4.393e+01 k fail RHS V[BJT1.L3.i]= 3.518e+01 (1e+03x) dV= 5.772e-01 dI= 8.929e-05
iter = 7 RHS I= 1.385e+04 V= 4.898e+01 k fail RHS V[BJT1.L3.i]= 2.882e+01 (1e+03x) dV= 5.746e-01 dI= 5.642e-05
iter = 8 RHS I= 1.430e+04 V= 4.393e+01 k fail RHS V[BJT1.L3.i]= 3.518e+01 (1e+03x) dV= 5.741e-01 dI= 1.987e-04
iter = 9 RHS I= 1.397e+04 V= 4.898e+01 k fail RHS V[BJT1.L3.i]= 2.882e+01 (1e+03x) dV= 8.614e-01 dI= 1.092e-04
iter =10 RHS I= 1.425e+04 V= 4.393e+01 k fail RHS V[BJT1.L3.i]= 3.518e+01 (1e+03x) dV= 2.873e-01 dI= 2.015e-04
iter = 1 RHS I= 1.916e+08 V= 8.736e+08 k fail RHS I[Vs]= 2.187e+08 (4.9e+02x) dV= 1.406e+06 dI= 6.686e-01
iter = 2 RHS I= 8.429e+04 V= 5.647e+02 k fail RHS V[Var1.L1.i]= 1.439e+03 (1e+03x) dV= 4.604e+00 dI= 3.090e-04
iter = 3 RHS I= 6.249e+04 V= 4.834e+02 k fail RHS V[Var1.L1.i]= 6.093e+02 (1e+03x) dV= 1.378e+01 dI= 2.232e-04
iter = 4 RHS I= 4.111e+04 V= 4.072e+02 k fail RHS V[Var1.L1.i]= 6.093e+02 (1e+03x) dV= 1.383e+01 dI= 1.468e-04
iter = 5 RHS I= 1.040e+05 V= 4.834e+02 k fail RHS V[Var2.L1.i]= 2.335e+03 (1e+03x) dV= 3.143e-01 dI= 3.700e-04
iter = 6 RHS I= 6.706e+04 V= 4.072e+02 k fail RHS V[Var2.L1.i]= 1.761e+03 (1e+03x) dV= 1.378e+01 dI= 2.233e-04
iter = 7 RHS I= 4.111e+04 V= 4.834e+02 k fail RHS V[Var2.L1.i]= 2.335e+03 (1e+03x) dV= 1.380e+01 dI= 1.468e-04
iter = 8 RHS I= 1.040e+05 V= 4.072e+02 k fail RHS V[Var2.L1.i]= 1.761e+03 (1e+03x) dV= 3.143e-01 dI= 3.700e-04
iter = 9 RHS I= 6.706e+04 V= 4.834e+02 k fail RHS V[Var2.L1.i]= 2.335e+03 (1e+03x) dV= 1.378e+01 dI= 2.233e-04
iter =10 RHS I= 4.111e+04 V= 4.072e+02 k fail RHS V[Var2.L1.i]= 1.761e+03 (1e+03x) dV= 1.380e+01 dI= 1.468e-04
iter = 1 RHS I= 1.916e+08 V= 8.736e+08 k fail RHS I[Vs]= 2.187e+08 (4.9e+02x) dV= 1.409e+06 dI= 4.179e-02
iter = 2 RHS I= 1.026e+06 V= 9.981e+03 k fail RHS I[X4.HPFET1.d]= 4.972e+06 (2.1x) dV= 1.617e+03 dI= 2.276e-04
iter = 3 RHS I= 7.239e+05 V= 1.684e+04 k fail RHS I[X4.HPFET1.d]= 3.253e+06 (1.4x) dV= 2.940e+02 dI= 1.669e-04
iter = 4 RHS I= 5.059e+05 V= 8.591e+03 k fail RHS I[X4.HPFET1.d]= 2.416e+06 (1x) dV= 1.471e+02 dI= 1.133e-04
iter = 5 RHS I= 3.011e+05 V= 1.684e+04 k fail RHS I[X4.HPFET1.g]= 4.561e+05 (4.6x) dV= 2.206e+02 dI= 5.625e-05
iter = 6 RHS I= 1.810e+05 V= 8.591e+03 k fail RHS I[X4.HPFET1.g]= 9.427e+05 (9.6x) dV= 7.309e+01 dI= 4.336e-07
iter = 7 RHS I= 1.607e+04 V= 1.684e+04 k fail RHS V[BJT1.L6.i]= 8.571e+04 (1e+03x) dV= 7.505e+01 dI= 8.549e-07
iter = 8 RHS I= 2.905e+05 V= 8.591e+03 k fail RHS I[X4.HPFET1.g]= 1.392e+06 (14x) dV= 7.726e+01 dI= 5.700e-05
iter = 9 RHS I= 2.285e+05 V= 1.684e+04 k fail RHS I[X4.HPFET1.g]= 4.819e+05 (4.9x) dV= 2.944e+02 dI= 5.462e-05
iter =10 RHS I= 1.744e+05 V= 8.591e+03 k fail RHS I[X4.HPFET1.g]= 9.284e+05 (9.4x) dV= 7.452e+01 dI= 2.815e-06
It seems some convergence problem with this devices, isn't it? Any tips to fix it?
Ty very much!