Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Hybrid pi model for transistor

Status
Not open for further replies.

mt09

Newbie
Joined
Jan 4, 2021
Messages
1
Helped
0
Reputation
0
Reaction score
0
Trophy points
1
Activity points
13
Could anyone help me with this problem? I need to show that the circuit of the figure behaves in an inductive way. For this, the complete hybrid pi model of transistors should be used to extract the impedance and show that the circuit really behaves like an inducer. Thank you in advance!

26F2EC39-F7A2-4C89-AD0F-FD42CEC30810.png
The transistor can be replaced by its complete hybrid pi model, as shown in the figure below
B0E10A08-7679-45CD-94E2-7ED43A9E3149.jpeg
 
Last edited by a moderator:

Solve for Zin and Zout to look at behavior. Use PFE on your
solutions to get at the actual resulting element values so you
can see what dominates.

Best done in LaPlace.


Regards, Dana.
 

Capacitors and inductors are often counterparts.

The capacitor with resistive divider is able to display inductive action. It can be seen by examining AC square waves going through either your green/yellow network or green/red network.

There are gyrator circuits which use a resistor and capacitor to produce inductor behavior. It starts with the capacitive time constant and adds an active component, in order to mimic an inductive time constant.

An op amp or transistor is the active (amplifying) component.
Your transistor circuit appears to contain a similar concept.
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top