moonnightingale
Full Member level 6
For term like exp(-1.5 s) x 3/(s^2+4s+3) We can take the Ztransform or discrete form by this code
clc
Td=1.5;
T=1;
num=[0 0 3];
den=[1 4 3];
Gs=tf(num,den,'InputDelay',Td)
Gz=c2d(Gs,T)
[numz,denz]=tfdata(Gz);
[A,B,C,D]=tf2ss(numz{1},denz{1})
But when i am having exp(1.5 s) x 3/(s^2+4s+3) (( negative sign not there how to calculate)) s is Laplace Domain
Thanks
clc
Td=1.5;
T=1;
num=[0 0 3];
den=[1 4 3];
Gs=tf(num,den,'InputDelay',Td)
Gz=c2d(Gs,T)
[numz,denz]=tfdata(Gz);
[A,B,C,D]=tf2ss(numz{1},denz{1})
But when i am having exp(1.5 s) x 3/(s^2+4s+3) (( negative sign not there how to calculate)) s is Laplace Domain
Thanks