Mar 7, 2007 #1 B baby84 Newbie level 1 Joined Mar 7, 2007 Messages 1 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 1,287 cos(5Θ1)+cos(5Θ2)+cos(5Θ3)+cos(5Θ4)+cos(5Θ5)=0 cos(7Θ1)+cos(7Θ2)+cos(7Θ3)+cos(7Θ4)+cos(7Θ5)=0 cos(11Θ1)+cos(11Θ2)+cos(11Θ3)+cos(11Θ4)+cos(11Θ5)=0 cos(13Θ1)+cos(13Θ2)+cos(13Θ3)+cos(13Θ4)+cos(13Θ5)=0 cos(Θ1)+cos(Θ2)+cos(Θ3)+cos(Θ4)+cos(Θ5)=5×0.8=4
cos(5Θ1)+cos(5Θ2)+cos(5Θ3)+cos(5Θ4)+cos(5Θ5)=0 cos(7Θ1)+cos(7Θ2)+cos(7Θ3)+cos(7Θ4)+cos(7Θ5)=0 cos(11Θ1)+cos(11Θ2)+cos(11Θ3)+cos(11Θ4)+cos(11Θ5)=0 cos(13Θ1)+cos(13Θ2)+cos(13Θ3)+cos(13Θ4)+cos(13Θ5)=0 cos(Θ1)+cos(Θ2)+cos(Θ3)+cos(Θ4)+cos(Θ5)=5×0.8=4
Mar 8, 2007 #2 H hamidrezakarami Full Member level 3 Joined Feb 26, 2007 Messages 180 Helped 45 Reputation 88 Reaction score 41 Trophy points 1,308 Activity points 2,162 Re: how to solve this equation using mathcad or Newton-Raphs i can't understand your problem. what's the meaning of cos(5Θ1)?
Re: how to solve this equation using mathcad or Newton-Raphs i can't understand your problem. what's the meaning of cos(5Θ1)?