hi
i am implementing active inductor in cadence for that i need to plot the input impedance at various frequencies,so help me about what analysis i need to choose and what are the output variables i need to consider...etc.
iam doing simulations in cadence virtuoso.
please help me out.
Put DC voltage source (V0 for example) connected to to the input with Vdc=Vop, where Vop is operation point of your active inductor. Set AC magnitude to 1mV or 1V.
Run AC analysis. Than using calculator plot VF(V0)/IF(V0). It will plot input impedance vs. frequency.
hi for my inductor i had taken 600mv as operating point voltage and 150mv as ac voltage, when i am using the expression VF(V0)/IF(V0). in my case it is V2 not V0. a messge window is coming.
{evaluation error(ERROR"eval"36 t nil ("Error"eval :unbound variable"V2)))Expression:VF(V2)/IF(V2)}
one thing i did not understood is why we need to take it as VF instead of V, becoz i dont know the syntax for that.
please clarify it.
Frankly speaking you shouldn't type this expression by yourself. Use mouse, calculator window(CW) and schematic window(SW). The steps are as follows:
CW: click VF
SW: click node you are want to put unto CW. The exspression will be apeared in CW
CW: click IF
SW: click device terminal the current of that you want to put into CW. The expression in CW will be changed.
CW: click "/", then click plot.