Hi Prashant,
Sorry the late respone.
I had used this command way way back. so not really sure how to answer your question appropriately.
The overall box around a particular layout design will be a rectangle with say coordinates as [(x0,y0) , (x1,y1), (x2,y2) , (x3,y3)] , where x-axis is the horizontal and the y-axis is the vertical axis . now these coordinates represent the left-hand-lower-corner , the left-hand-top-corner , the right-hand-lower-corner and the right-hand-top-corner.
by using the command i expect the whole layout to be shifted to origin, i.e., (x0,y0), the left-hand-lower-corner, would now be shifted to (0,0) and (x1,y1), the left-hand-top-corner, to (0,y1) where y1 is now the height of the layout box but which is kept at x=0, or kept at x-axis.
If your layout is in an oblong shape then the 'move to origin' doesn't really help since you might find it difficult to find the exact (x0,y0) , i.e., the left hand lower corner. also by moving your cursor there and move to origin might result in human error of how accurately you use the mouse to bring the cursor to that point (which you think is the left-had-lower-corner of your layout)
It is required to shift it to (0,0) since it helps in layout of a chip with sub blocks. and some foundries need the axis shifted to (0,0) of the entire Chip layout.
Is that what you were asking in the lowerleft question? because I havnt dug deep into this SKILL code to see what else it could do, and i have moved out of layout for now.