How to measure the gain of LDO in cadence

Status
Not open for further replies.
S

Savankumar

Newbie level 5
Joined
Mar 14, 2019
Messages
8
Helped
0
Reputation
0
Reaction score
0
Trophy points
1
Activity points
82
Hey Team,
I am designing the Low Voltage dropout regulator.
My input voltage is 2V and the output required is 1.2V. I used a two-stage op-amp as my error amplifier.PMOS devise as pass element.
I am measuring my gain between y and input as shown in my diagram providing ac signal at the input side. Is this the correct way to measure the gain in LDO?
And by doing this I am getting very less gain so can anyone explain to me how to increase it? For my op-amp, the gain is 60dB.
Thank you in advance



 

Your input difference voltage is {vbg-vin1}, I would tap that
with a vcvs to get a ground referred input difference voltage
that's real-time-valid for all analyses. Use this as the gain
denominator and the phase "zero reference".
 

The annotated DC node voltage values(maybe not they are annotated?) are very bad, the PMOS passing device's gate voltage is almost 0V.
1st solve that to control the PMOS with smaller |Vsg|. Otherwise it is not even an LDO. An enhanced resistive driver perhaps.
 

Status
Not open for further replies.

Similar threads

Menu
Log in
Register
Cookies are required to use this site. You must accept them to continue using the site. Learn more…