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How to efficiently isolate an optional power source from main power circuit?

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player80

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Hi,

I'm using some chipset via USB which allows an input voltage between 4 - 20V

In order to block 12V from injecting to the 5V power circuit I'm using a diode on the 5V supply.
While this works fine with 12V (since the current is low), when I power the chipset with 5V the current is quite high which results that this diode is heating up quite a lot.

Does anyone know any better way to isolate the main input voltage?
 

Hi,

Please show your schematic, and add some current informations.

Klaus
 

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