Jeetkumar
Member level 1
Hi all,
I have 1 inch copper tube with 30 cm diameter of circular structure made from copper tube. the resonance frequency for my simulation is 17.83 MHz. i just want to measure the quality factor. can you plz help me with this, i came across formula which states Q = fc/(f2-f1)
Thanks in advance.
I have 1 inch copper tube with 30 cm diameter of circular structure made from copper tube. the resonance frequency for my simulation is 17.83 MHz. i just want to measure the quality factor. can you plz help me with this, i came across formula which states Q = fc/(f2-f1)
Thanks in advance.