If you actually mean same area under the curve, the sine wave has a higher power.If the square wave has an amplitude of 1, the sine wave must have a peak amplitude of pi/2 for same area. Square wave's power is 1.0 but sine wave's power is 1.11 then.
You don't have to refer to spectral components to calculate the power, simply evaluate the integral of squared amplitude.
A one line solution is to speak in terms of area under the curve of v square plot for comparison of such situations.
This is subject to
1. Constant load.
2. Same frequency of square and sine waves. Else long time integration.
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tellMeDaBasix,
Consider a sine wave voltage with a peak amplitude of 1V driving a 1 Ohm load. The RMS value of the sine wave is .707V. The power = V^2/R = 0.5W. The average value of the sine wave is 2/pi = .637.
.
Now consider a square wave with the same average value of .637. The RMS and average values of a square wave are the same (.637 in our case). The power dissipated by the 1 Ohm load is V^2/R = (.637^2) = .406W.
.Conclusion: The sine wave has more power.
Regards,
Kral
TellMeeDaBasix,
In your original post, you were considering a sine wave and a square wave with equal areas (average values). In your last question, you are considering a sine wave and a square wave with equal peak to peak values. In this case, the square wave has a higher RMS value and hence more power will be delivered to the load (speaker).
Regards,
Kral
Like a CRO but has an function to save and modify waveforms/signals. It also has a facility to connect to computer and get pre stored waveforms.
It has 3 modes of operation.
1. Free running mode.
2. Store
3. auto store... or something I dont exactly remember the modes
Your acoustic signal chain adds an arbitray frequency characteristic to your setup. If you get a higher microphone signal level, this hasn't to do with "power" of the squarewave. Apparently the signal chain is preferring the harmonics to the fundamental.