How many address lines are needed for a 64Kb segment with each register having 512 b

[kumar_eee]

How many address lines are needed to address a 64Kb segment with each register storing upto 512 bytes

 

[tamerakshar]

Re: Solution plz


64k=2^6*2^10=2^16
now you should devide it by 512 to get the no of addressed locations
2^16/2^9=2^7=128 addressed location of size 512
which will need 7 address lines
TeE ThE EdE