Non AMP

how do the exponent algorithm implement in verilog?

Thread starter openwindows
Start date Mar 23, 2003

Status: Not open for further replies.

Mar 23, 2003

#1

O

openwindows

Junior Member level 3

verilog exponent

1:
(1-2^-n)
2:
(1-2^-n)^6
3:
(1-2^-n)^1/4

Apr 24, 2011

#2

rohitchawda

Newbie level 5

Exponent works as "**"

for example: 2 raised to power 3 can be written as 2**3

Status: Not open for further replies.

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