How can I get each byte of 32-bit floating point by using C

[BabyTiger]

I need to get each byte of 32-bit floating point variable by using C programming
Ex. Variable Z is the floating point has 4 byts (BYTE0:BYTE1:BYTE2:BYTE3)
I need to put
BYTE0 into A where A is unsigned char
BYTE1 into B where B is unsigned char
BYTE2 into C where C is unsigned char
BYTE3 into D where D is unsigned char

Please help me, I need to write in C programming.

Best Regards

 

[CMOS]

Re: How can I get each byte of 32-bit floating point by usin

Here you go.

#include <stdio.h>
#include <conio.h>


void main(void)
{
	float x;
	unsigned char bytes[4];

	x = 1087.9845F;

	*(float *)(&bytes[0]) = *(float *)(&x);

	printf("B0=%x\nB1=%x\nB2=%x\nB3=%x\n",bytes[0],bytes[1],bytes[2],bytes[3]);
}

 

[hero0765]

Re: How can I get each byte of 32-bit floating point by usin

Using UNION

main()
{
union
{ unsigned char ch[4];
float d;
}s;

s.d=0xffffffffh;

}

you do as above
the BYTE0 of variable d will be into the ch[0]
the BYTE1 of variable d will be into the ch[1]
the BYTE2 of variable d will be into the ch[2]
the BYTE3 of variable d will be into the ch[3]

 

[jhbbunch]

Re: How can I get each byte of 32-bit floating point by usin

This will work:

//**********************************
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{

float f = 3332.54543;
unsigned long *l;
unsigned char *p;

l = (unsigned long *)&f;
p = (unsigned char *)&f;

printf("Here they are: %lx, %hx, %hx, %hx, %hx\n", *l, *p, *(p+1), *(p+2), *(p+3));

system("PAUSE");
return 0;
}

//*************************************

This is the output:

Here they are: 455048ba, ba, 48, 50, 45


I used the devc compiler.