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# How can I calculate the value of bondwire?

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#### kella

##### Member level 3
how can I calculate the value of bondwire? What should be the lenght and diameter of it?

thanks
/K

wire bonding inductance

Hi, Kella:

Some people use the value of 1 nH per mm as a rule of thumb for typical wire bonds. In fact, it should be related to the radius as well as the length. It should also be related to the ground plane and the surronding such as coupled wire bonds. Basically, the current loop is critical. Regards.

bonding wire inductance

But how should i decide about the length of bond wire i need for a cascode LNA?

i am new to this area so please tell me should the length of bondwires at all terminals of transistor be same?

i tried with D=10 um and length = 500 um. after inserting bondwires S11 is changed alot as i already have a inductor in series to the gate of transistor.

regards

/K

wire bond inductance

Yes 1nH/mm is a good aproximation.
Of course as wire is shorter and thicker, as inductance is smaller.
2 parallel wire reduce inductance even if they are mutually coupled.
Two wire give less inductance than one wire (or ribbon) of the sum section.

D=10 um is very thin, may be too mutch thin.
L=500um is very long, may be too long

Usually, gold, wedge, bond wire have a maximum L/D = 15

typical bond wire inductance

Yes. L = 500 microns and D = 10 microns may create quite significant inductance.

bond wire inductance calculator

since i am using cascode configuration for my LNA and after adding bondwires of L=500 um and D=10um at the terminals of transistors the input impedance changes significantly. I have also added a degenration inductor which has very small value i.e less then 0.5 nH so can some tell me :

do i use same bondwire i.e with same lenght and D or can I use different values of bondwires?

what should be the typical value of bondwire inductance?

thanks
/k

bondwire inductance

1 nH/mm is a typical value for bond wire inductance.

gold wire inductance

If possible, You may try to increase the wire diameter. 10 um (4 mils) is extremally thin. Less than suggested in most application. For example, the smaller HEMT made by Eudyna (Fujitsu) or Cel (NEC) have pads that support 17um thick wire. and is the 17 um Au wedge, the suggested wire!

bond wire inductor

The inductances of bonwires are not sufficient to design circuits. Also, mutual inductances and as well as package parasitic capacitances must be well modeled and should be taken into account when doing simulations. Especially over 2GHz, parasitic capacitances regarding to substrate,diepad and neighbourgh pins and bondwires must be very well modeled by using either Ansoft 3D Extractor or better HFSS 3D EM simulations.

I have had many bad troubles with these unwanted effects of a package at 5.8GHz and many of them are not solved yet..

bonding wire inductor

The D=10um bonding wire is too thin. According to my experience, a typical diameter of 0.98mil/1mil/1.2mil(1mil=25.4um) gold wire is widely used in industry applications. As such, a very good rule of thumb to calculate the Parital Inductance is 1nH/mm, which is also the value you can get through most of the 3D qusia-static EM solvers such as Ansoft Q3D, PaksiE, Cadence APE3D etc. If you want to account for the bond wire effects at the system level, the Loop Inductance rather than the Partial Inductance should be used, which takes into account the effects of ground plane effect, coupling effect etc. And most of the time, a 3D EM full-wave solvers is needed(such as Ansoft HFSS, CST MicrowaveStudio).

Again, take note that a specified wire has fixed Parital inductance which, in most of the cases, is what the package parasitics L refers to. However, the same wire has different loop inductances when used in different systems, which is what a system design engineer need to take care of.

bond wire inductance calculation

I am no expert, but I would suggest to isolate the problem to the bond wires,
try some of these configurations suggested and measure your results.
if there is little or no change to S11, then it is probably something else as BigBoss stated it could be, but if you see significant changes then it would logically be the BWs

inductance of a wire

Hi, All:

This topic is quite interesting. Many of us just gave some comments based upon previous experiences and some common senses. I am curious how much of what we discussed is true or very solid, and I tried to simulate some wire bond cases with the dimensions discussed here using a full-wave EM simulator (IE3D). Following are what I got and the 3 projects are included in the attachment.

As you can see, L is certainly decreasing with diameter. However, the rate is not so high. I believe it should be in the LOG scale. For the coupled wire bonds, the self-L just decreases slightly while the mutual-L can be quite significant.

As you can, the 1 nH/mm rule is still approximately true.

-------------------cases and results----------------------------------
100 um GaAs substrate
75 um by 75 um Bondpads
Wire bond height (from base): 98.5 um
Approximate Wire bond length: 500 um
Approxiate total length (including bondpads): 600 um
Wire bond to wire bond center to center distance: 100 um

One 17 um thick One 10 um thick Coupled 17 um thick

L(1,1) @ 1 GHz 0.4115 nH 0.4683 nH 0.4107 nH
L(1,1) @ 10 GHz 0.3905 nH 0.4424 nH 0.3891 nH

---------------------------------------------------------------------------------

Regards.
[/b]

klng1025 and Canosa

Points: 2

### klng1025

Points: 2
bondwire inductor

thanks guys for such a nice response. Can I open those IE3D files in @DS? I have access to @DS only.

bond wire inductivity

Hi, Kella: You can try an eval license from www.zeland.com. Thanks!

inductance of wire

Jian the eval liscense works for Linux not Win.

inductance calculation bond wire

Hi, Kella: You might pick the wrong item. The evaluation license works for the Windows. Only the IE3D engine is working for Linux and it is a separated item. Please download ALL PRODUCTS FROM ZELAND for the Windows eval. Regards.

inductance of gold wire

I got this info from the manufacturer of GaAs pHEMT Transistor :

--------------------------------------------------
You just have to use it with :
- Wu = 20 (unit finger width)
- N=6 (number of fingers).
Note that the model includes only intrinsic Ls, Lg and Ld inductors.
for a single 25.4µm wire).
The model is validated to 60GHz and can be used for linear analysis
as well. You can thus extract S-parameter to 60GHz.
------------------------------------------------------

/K

bond wire inductance model

Hi, Keller: Yes. 0.8 nH / mm is a good value. I can see it matches the IE3D results always perfectly. Certainly, the L should be decreasing with frequency. Also, the mutual L may be critical if you use multiple wire bonds in the fingers. Regards.

0.8nh/mm

One 17 um thick One 10 um thick Coupled 17 um thick

L(1,1) @ 1 GHz 0.4115 nH 0.4683 nH 0.4107 nH
L(1,1) @ 10 GHz 0.3905 nH 0.4424 nH 0.3891 nH

do you ever measure the inductance of wirebond @20GHz ?

mutual inductance of bond wires

Hi, Scuba:

The data is not measured one. I simulated in the IE3D Full-Wave EM Simulator and I attached all the results earlier. Here are the results with more (selected)frequency points. It is interesting to see the calculated L(1,1) value matches the specification from the manufacturer (provided by Keller in the previous e-mail). Certainly, the manufacturer of the transistor claimed the model of L = 0.8 nH/mm will work up to 60 GHz might be over estimate. For 500 um length, it is almost half a waveguide wavelength in a typical 100-um thick GaAs circuit. Lumped element model should not work. From what I see, the lumped element model should still work up to 15 GHz. Certainly, it will be much better to use the primary s-parameter results from full-wave EM simulators. Regards.

----------------results start----------------------------------------------------
WB length = 500 um with 50 um extra length in each bond pad.
Coupled WBs are separated by 100 um from center to center.
The circuit should be modeled as distributed circuit over
about 15 GHz. Using lumped element may cause loss of accuracy.

All L's are in nH.

1 WB 1 WB 2 WBs
D=10um D=17um D=17um
L(1,1)@1 GHz 0.4683 0.4115 0.4107
L(1,1)@10 GHz 0.4446 0.3905 0.3891
L(1,1)@20 GHz 0.3816 0.3424 0.3422
L(1,1)@30 GHz 0.2876 0.2674 0.2687
L(2,1)@1 GHz N/A N/A 0.1170
L(2,1)@10 GHz N/A N/A 0.1128
L(2,1)@20 GHz N/A N/A 0.1026
L(2,1)@30 GHz N/A N/A 0.0858
--------------results end----------------------------------------------

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