Thanks, I must admit we are using the BTS6163 downstream of a PSU which has a built in current limit to 19A in the event of output short circuit...so therefore a short circuit downstream of the BTS6163 would never actually activate the BTS6163 to shut down, since the current through the BTS6163's internal FET would never get above 19 Amps.
(and thence the drain-source voltage across the internal fet of the BTS6163 would never get above 3.5V....and so "short circuit" would never be recognised.)
So it is a shame for us that these smart FETs rated to 60V dont have a definite short circuit protection current shutdown level..
You apparently misunderstand the meaning of L/R curve. It tells maximum inductance versus minimum load resistance or vice versa. You can have lower load resistance if the inductance is also lower.
Thanks, and presumably this is because they want to limit the amount of energy stored in the inductor by limiting the peak current of the shorted current…and thereby allow the BTS6163 to survive the short circuit event…..the situation is though that we may well have some 3uH of stray inductance in our wiring , though we definitely don’t have anywhere near 230milliOhms of stray resistance…we have much less than that…so I really am thinking that the BTS6163 is making too many stipulations for our system, and it actually isn’t even going to work for us at all.
Its just a shame there are no other smart fets rated to 60V with such low rds(on)…anywhere in the world.
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On page 5 of the BTS6163 datasheet, it says that the BTS6163 limits its current to 22A if it has 45V across its internal FET. Does this current limiting happen straight away?.....it seems very good for the BTS6163 to be able to limit the current down to 22A very quickly….would there be a much higher initial current than 22A whilst the BTS6163 attempts to limit the current down to 22A?
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Fig 3c, page 11 of the BTS6163 datasheet appears to show that the BTS6163 shuts off 2us [“td(sc2)”] after the V(ON) voltage goes above 1V.
This does not correspond to what it says on page 5 of the datasheet, where it says that the BTS6163 shuts down 2us after the V(ON) goes above VON(SC).
Where….
V(ON) = voltage across drain-source of the internal fet of the BTS6163
VON(SC) = 3.5V
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Fig 6b of the BTS6163 datasheet shows that the BTS6163 can be used to monitor the current through it. (Because the current flowing out of the I(IS) pin is a known fraction of the actual current in the internal power fet of the BTS6163….) The problem is that the ratio of “actual FET current” to I(is) current is very widely toleranced, at anywhere between 11000:1 to 8000:1
So the BTS6163 appears not to be an accurate current monitor.