Jul 29, 2010 #1 T the_falcon Member level 4 Joined May 28, 2010 Messages 72 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,286 Location Toronto Activity points 1,811 can anyone explain me as how it comes to 0.06 degrees <(1+j) - <(1 + (j+.2%)) the answer for this expression is 0.06 degrees and the lower_than symbol denotes the angular symbol here.' thanks in advance
can anyone explain me as how it comes to 0.06 degrees <(1+j) - <(1 + (j+.2%)) the answer for this expression is 0.06 degrees and the lower_than symbol denotes the angular symbol here.' thanks in advance
Jul 30, 2010 #2 P pavel_adameyko Full Member level 4 Joined Jun 23, 2010 Messages 190 Helped 52 Reputation 104 Reaction score 37 Trophy points 1,308 Location Belarus Activity points 2,338 Hi this expression can be written as arctan(1)-arctan(1.002) derivative of arctan()=1/(1+x^2) so its 1/2 at point x=1. thus arctan(1)-arctan(1.002)=-1/2*0.002=-0.001 rad = -180/pi*0.001 deg = -0.06 degree Regards, pavel.
Hi this expression can be written as arctan(1)-arctan(1.002) derivative of arctan()=1/(1+x^2) so its 1/2 at point x=1. thus arctan(1)-arctan(1.002)=-1/2*0.002=-0.001 rad = -180/pi*0.001 deg = -0.06 degree Regards, pavel.