BlackOps
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BlackOps said:solved the equations..well, now the answer is correct.
but i dont understand second equation!!!
from it i can conclude that currents are only entering node from three resistors! but it is not possible... can u explain second equation to me?[/quote
that is coz,
V1/20 + (V1 - V2)/40 = 10 ---- 1
V2/100 + (V2 - V3)/50 = (V2 - V1)/40 ------- 2
(V3 - V2)/50 + (V3 - V4)/10 = 2 - 2.5
V4/200 + (V4 - V3)/10 = 5 - 2
in 1, from the equ. written, current of V1 is downwad and that of the branch connecting V1 and V2 is from V1 to V2... so always whatever branch u are goin to take in the future.. u can not change this assumed direction.. so.. what u can say is, the current floes from left to right for branch having V1 and V2 vol. and it is V1-V2/40.
condsidering equ 2. v2/100 => downward cur. dir.
v2-v3 / 50 => from left to right.
but those 2 are outgoin currents.. and u have assumed ur direction of V1-V2 loop to be left to right whiuch says, its into the branch/node for this particulare node.. so its..
V2/100 + (V2 - V3)/50 = (V1 - V2)/40 its just the same current.. only incoming = outgoing..
Hope it helps.. in case of any confusiioons.. pls revert back..
/Am
BlackOps said:picus, best book about circuit analysis is, Engineering Circuit Analysis, by Hayt and Kemmerly
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