Where is vout- and vout+ connected? There are opamps in this device but adc_in4 and vout- is directly connected to opamp negative and positive inputs.
In this case isn't it force to make adc_in4 ~= vout-?
May be i am wrong, not sure, but i think something is missing in the schematic.
At first sight this is seems a non-standard config of opamps.
Main issue is -- the + inputs of the 2 opamps are designated as OUT- and OUT+. Without knowing what this is conencted to it is almost impossible to work out what this circuit does.
I think it could be a 2-opamp differential amp config... where OUT- and OUT+ are actually inputs from the sensor. In that case it is a standard config, except for the 220 ohm resistor, and also the point at which the ADC_IN value is taken from.
i also think its differential amp, but i know want what is the gain if its differential amp..........
i got the your answer but above circuit is not amplifying correct, it is giving the constant voltage of the 10k pot......