Aug 15, 2006 #1 V v9260019 Member level 2 Joined Jun 5, 2005 Messages 47 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,286 Activity points 1,680 **broken link removed** Hello all, how to prove the above equation thanks a lot
Aug 15, 2006 #2 M me2please Full Member level 3 Joined Aug 7, 2004 Messages 180 Helped 14 Reputation 28 Reaction score 0 Trophy points 1,296 Activity points 1,113 https://en.wikipedia.org/wiki/Cauchy-Schwarz_inequality
Aug 18, 2006 #3 neils_arm_strong Full Member level 5 Joined Jan 5, 2006 Messages 288 Helped 22 Reputation 44 Reaction score 3 Trophy points 1,298 Location Bangalore, India Activity points 3,247 Traeting x(t) as a vector,we can say any vector component is always less than or equal to its absolute value. e^st has the same modulus as e^(sigma)t.
Traeting x(t) as a vector,we can say any vector component is always less than or equal to its absolute value. e^st has the same modulus as e^(sigma)t.