it means the posted ckt is right and VP will Connect to 2 and VN to 1Hi,
generally for non inverting output:
* Vp on the more positive terminal of the shunt
* Vn on the more negative terminal of the shunt
Klaus
But your schematic is a riddle rgarding polarity.
Klaus
Wrong.But if i apply the current direction then
point 2 will be more negative so it will be connect to VN
It becomes quite clear if you input voltage source and bridge rectifier.But your schematic is a riddle regarding polarity.
Yes. Making node 2 more positive than node 1.The current will flow through MOSFET.
You may use any signal as GND. But you should show us in your circuit.Then the overall ckt gnd will be node 2..
You are able to measure the actual shunt voltage, not shunt voltage plus PCB voltage drop as with a single ended amplifier. (4-wire or "kelvin sensing" resistor connection)What is the significance of Differential op-amp..?
Referring to usual PFC circuits, node 2 (MOSFET source) is typically connect to (mains side) common ground. E.g. because it's also the gate driver and DC bus ground.
How can you know? The picture doesn´t show "positive signal".Where positive signal is on the VN..
generally for non inverting output:
* Vp on the more positive terminal of the shunt
* Vn on the more negative terminal of the shunt
..is a bit vague.max 100mv
It can be a digital IO --> not very likelyWhere does the signal go to:controller
You need a rail-to-rail output OPAMP, you need an OPAMP with common mode input voltage range that includes GND. Mind that even with rail-to-rail output you will lose some mV close to GND.Single supply or dual supply:single supply
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