Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Having Trouble With Designing IIR Filter on Frequency Transformation

Status
Not open for further replies.

yhatagishi

Junior Member level 3
Junior Member level 3
Joined
Apr 10, 2013
Messages
26
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Visit site
Activity points
1,508
Hello all,

As written in title, I am having trouble with frequency transformation.
There are three problems I am encountering right now.

(1) Over-specification band pass filter
I designed a 4th order chebyshev low pass filter which does satisfy given specification, in which
- pass band edge frequency fp = 6500 Hz,
- stop band edge frequency fs = 7500 Hz,
- pass band ripple Ap = 1 dB,
- stop band attenuation As = 10 dB, and
- sampling frequency fsamp = 50 kHz.

However, after transforming this low pass filter to band pass filter with
- low pass band edge frequency fpl = 7500 Hz and
- high pass band edge frequency fph = 8500 Hz
I got the 8th order filter with the gain characteristic shown in the graph attached to this thread.
iir-bpf.jpg

Obviously, it's over my specification and I wonder why this happens and want to get a filter that follows given specification.

(2) Peaky band pass filter
When I designed a 13th order chebyshev low pass filter and created band pass filter using frequency transformation,
I got the 26th order filter with peaky ripple, which is over than 10 dB...

(3) Low pass band band pass filter
When I designed a 9th order chebyshev low pass filter and created band pass filter using frequency transformation,
I got the 18th order filter with pass band gain lower than -40 dB...


As written in (1), the low pass filter DOES satisfy given specification, but the band pass filter does not.
The formula I used to do frequency transformation is below

z-1 =
z-2 - (2*a*k*z-1)/(k+1) + (k-1)/(k+1)
-----------------------------------------
(k-1)*z-2 /(k+1) - (2*a*k*z-1)/(k+1) +1


Can anybody help??


Regards,
Yukihiro
 

I solved this problem by myself.
I was designing the filter by maple and changing digits in maple helped me.
 

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top