getting adc result of 8 bit values instead of 10 bit values in lpc2129 programming

[rangerskm]

i had attached the code for lpc2129 which is compiled sucessfully in keil uvision 4 .but getting adc output of only 8 bits instead of 10 bits.checked with adc debugger in keil and also in terminal in isis proteus.kindly help me in this.

#include "lpc21xx.h"
#define Fosc 12000000
#define Fcclk (Fosc*5)
#define Fcco (Fcclk*4)
#define Fpclk (Fcclk/4)
#define UART_BPS 9600     //SET BAUD RATE
//function prototype

void DECtoASCII(unsigned int data);
void Delay(unsigned char Ticks);
void init_UART0(void);
void UART0_Sendbyte(unsigned char data);
void UART0_Sendstr(unsigned char *str);
void ADC_init(void);
unsigned char ADC_Conversion(unsigned char channel);
////////////////

unsigned int ADC_Data1=0;
unsigned int ADC_Data2=0;
unsigned char TEMP[5];
double data;

///////////////

void DECtoASCII(unsigned int data)
{ 
	signed int i,local[5]={0,0,0,0,0};
	for(i=0;i<4;i++)
	 { local[i]=data%10;
		data= data/10;
	 }
	for(i=4;i>=0;i--)
	 { 
		 UART0_Sendbyte(local[i]+48);
		 
		 	 }
	 
	 
}
void Delay(unsigned char Ticks)
{
	unsigned int i;
  	if(Ticks==0)
		{
   		Ticks=1;
		}
	for(;Ticks>0;Ticks--)
	   {
      for(i=0;i<60000;i++);
	   }
	
}
void init_UART0(void)
{
	unsigned int Baud16;
	U0LCR=0X83;
	Baud16=(Fpclk/16)/9600;
	U0DLM=Baud16/256;
	U0DLL=Baud16%256;
	U0LCR=0X03;
	
}
 
void UART0_Sendbyte(unsigned char data)
{
	U0THR=data;
	while((U0LSR&0X40)==0);
}


void UART0_Sendstr(unsigned char *str)
{
	while(*str)
	{
		UART0_Sendbyte(*str++);
	}
		
}
void ADC_init(void)
  { 
		//PINSEL0=0X01000000; //AD0.1 PIN SELECTED
		ADCR&=0X00000000;
		ADCR|=0X00000E00;   //CLKDIV=PCLK/(ADCCLK-1) =15/1000000-1   ADCCLK=E
		ADCR&=0XFFF1FFFF;   //NO BURST IE BURST=0; SOFTWARE CONTROLLED

		ADCR&=0XFF3FFFFF;   //TEST 1:0 00 NORMAL MODE
		ADCR&=0XF7FFFFFF;   //EDGE =0 CONVERSION ON FALLING EDGE
		ADCR|=0X00200000;   //PDN=1 ACTIVE ADC MODULE
	}
	

unsigned char ADC_Conversion(unsigned char channel)
{
	unsigned int temp=0;
	ADCR=((ADCR&0XFFFFFF00)|channel);
	
	ADCR|=(1<<24);
	while((ADDR&0X80000000)==0);//wait for the conversion to complete
	//temp=ADDR;
	temp=(unsigned int)(ADDR>>6)&0x03ff;
	return temp;
}

int main()
{ unsigned int val;
	PINSEL0=0X05 ;// enable UART0 RX AND TX PINS
	PINSEL1=0X05; //ENABLE AD0.1 AND AD0.2
	PINSEL2=0;
	VPBDIV=0X01;//15 MHZ
	init_UART0();
	ADC_init();
	  while(1)
		{
			UART0_Sendstr("ADC");
			val=ADC_Conversion(1);
			DECtoASCII(val);
		}
	   
	
}

 

[brunofunchas]

Hi!

In your code you are sending the data in a 8 bits format (char) so you will loose the 2 bits