Filter's trade-off between the loss and the Q

[jiangnancai]

I am puzzled about Filter's trade-off between the "loss" and the "Q".
It is said that a filter's large value of Q is at the price of "loss" in the pass band of the filter. But what's the reason? Is it only suitable for passive filter?

Who knows? Thanks

 

[deepa]

your question is abstract .what loss are you mentioning ?loss due to the non ideal inductors and capacitors or the power or what

 

[jiangnancai]

sorry,I am puzzled about the above discription too.
I guess that the "loss" is referred to the pass-band gain,which is smaller than 0dB