I want to simulate waveguides made up of lossless metals. For such structures, metal's refractive index is purely imaginary. What implication does it have for courant factor? We know that S <= min/sqrt(#dimensions). Since minimum refractive index in my simulation is now zero, does this mean that FDTD is incapable of handling this object?
I want to simulate waveguides made up of lossless metals. For such structures, metal's refractive index is purely imaginary. What implication does it have for courant factor? We know that S <= min/sqrt(#dimensions). Since minimum refractive index in my simulation is now zero, does this mean that FDTD is incapable of handling this object?
No. FDTD can handle most materials. But your 'lossless metal' confuses me a bit.
Can you translate it into 'normal' FDTD terms. Do you mean negative permittivity?
At a fixed frequency? Then the normal method would be to set up a dispersive model
for these parameters and then use ADE or (PL)RC to model such materials