steppermotor
Newbie level 6
Question: A continuous-time signal x(t) = cos(f(t)), where f(t) = w0 + sin(w0t), is to be sampled at a rate fs.
What is the system’s Nyquist sample rate if w0 = 1000/(2pi) r/s?
I believe that w0=2*pi*f --> f= (1000/2*pi)*(1/2*pi) = 25.33 Hz and then multiplying by 2 to get the Nyquist sampling rate of: 50.66 Hz.
Am I on the right track or do I need to take into account the w0+sin(w0t) in some manner. I thought about taking the derivative: w0cos(w0t), but not sure how this helps me.
What is the system’s Nyquist sample rate if w0 = 1000/(2pi) r/s?
I believe that w0=2*pi*f --> f= (1000/2*pi)*(1/2*pi) = 25.33 Hz and then multiplying by 2 to get the Nyquist sampling rate of: 50.66 Hz.
Am I on the right track or do I need to take into account the w0+sin(w0t) in some manner. I thought about taking the derivative: w0cos(w0t), but not sure how this helps me.