Very useful graph!
Firing angle is seen to be ~65° in first and last part of cycle to achieve 110Vrms from a 220Vrms signal.
At 65°, peak voltage would then be:
220 x √2 x sin(65) = 282 volts. Not that much different from 220x1.414 and still exceeding peak of 110Vrms signal by more than 125 volts.
the word AND in the above quote makes the sentence incorrect, you can have the first 65 degC or the last in an half cycle - but not both - for 110Vac rms from 230Vrms ...
unless that is what the poster was trying to say ...
the word AND in the above quote makes the sentence incorrect, you can have the first 65 degC or the last in an half cycle - but not both - for 110Vac rms from 230Vrms ...
unless that is what the poster was trying to say ...