Increase sampling
Hi
definetely there is a gain in sampling at a rate higher than the Nyquist one, and you can not filter it out as it was said before.
In order to prove my point do the following, let us assume that the Nyquist frequency require X samples from you signal, but you increment the sampling rate in a factor A, therefore, you have now AX samples of your signal. Take this AX samples and divide them in sets of A samples, find the average of them and you will end up with X samples for which the higher the value of A, the better the resulting signal resemble your noiseless signal.
good luck