ermai
Member level 1
A capacitor behaves as short when initially uncharged and sudden volatage is applied and open when fully charged.
But in feedthrough,a volatge variation is in a charged coupling capacitor.
A feedthrough effect by a coupling capacitor is as below:
in which C2 is a couplng capacitor to VL2,and in initial C1 and C2 are charged.
when the bottom plate of C2 changes from VL2 to VL3 (assume that VL3 is low than VL2 ),the upper plate changes from Vd to Vx.
My question is that may I say that beacuse the sudden voltage change in the charged coupling capcitor C2,the C2 acts as "short circuit" such that C1 discharges to C2.
But in feedthrough,a volatge variation is in a charged coupling capacitor.
A feedthrough effect by a coupling capacitor is as below:
in which C2 is a couplng capacitor to VL2,and in initial C1 and C2 are charged.
when the bottom plate of C2 changes from VL2 to VL3 (assume that VL3 is low than VL2 ),the upper plate changes from Vd to Vx.
My question is that may I say that beacuse the sudden voltage change in the charged coupling capcitor C2,the C2 acts as "short circuit" such that C1 discharges to C2.